Jets quarterback Ryan Fitzpatrick has been named AFC Offensive Player of the Week for his direction of the Jets offense in their 37-31 Thursday night victory at Buffalo.
Fitzpatrick completed 24 of 34 passes for 374 yards, a 5-yard touchdown pass to Eric Decker in the game, and no turnovers, which produced a 116.5 passer rating. He added 21 yards on five carries.
For the game the Jets offense amassed 28 first downs and 493 yards and went on seven drives of 56 yards or longer, all of which produced red zone points.
"It's fun with everybody involved and everybody making plays, and the fact that it was a game that we fell behind in the second half," Fitzpatrick said Monday, reflecting on the Jets' first win of the season and first over the Bills since 2013. "The confidence in the huddle and the way the guys felt, the way that we knew we were going to get in the end zone, that was all good for us."
This is Fitzpatrick's third AFC Player of the Week award with the Jets. He also took home the league honor after last year's Week 14 win over Tennessee and Week 16 overtime triumph over New England. Further, it was the fifth POW award of his 12-year career. He won the NFC award once as a St. Louis rookie in 2005 and the AFC award once with Tennessee in 2013 before coming to the Jets.
Fitzpatrick wasn't waiting for any honors and accolades from the primetime win. He and the Jets returned to work focused on the next task ahead, the Chiefs at Kansas City on Sunday.
"The NFL is crazy in that we're only as good as what we do this week," he said. "We're not going to sit and — dwell wouldn't be the right word, but we're not going to sit and celebrate last week because we have to move on. We have a team that last year won 11 straight and were a playoff team and have played very well already this year and it's a very tough place to play, so we're already trying to get ready for that."